Practice portal › Waves › Beats
Asked in JEE Main Online 2018 · Unknown fork frequency and tuning
For a fixed tension f∝1/L. Let the 1 m wire sound at f₀; then the 0.95 m wire sounds at (f₀)/(0.95).
The fork lies between them: f₀+5=(f₀)/(0.95)-5.
10=f₀(1/(0.95)-1)=0.0526f₀, so f₀=190 Hz and the fork is at 190+5=195 Hz.
Reading this solution needs no sign-in. You only sign in to practise against the clock and keep your progress.
Practise this with a timer