Practice portal › Waves › Standing Waves in Strings

A sonometer wire of resonating length 90 cm has a fundamental frequency of 400 Hz under a certain tension. Under the same tension, the resonating length for a fundamental frequency of 600 Hz is ______ cm.

Asked in JEE Main 5th April 2nd Shift 2024 · Sonometer

Answer: 60

Step-by-step solution

At fixed tension and linear density, f∝1/L, so f₁L₁=f₂L₂.

L₂=(400×90)/(600)=60 cm.

More Standing Waves in Strings questionsAll Standing Waves in Strings questions →

Reading this solution needs no sign-in. You only sign in to practise against the clock and keep your progress.

Practise this with a timer