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Asked in JEE Main 29th July 2nd Shift 2022 · Transverse wave on a string
μ=(10×10⁻³)/(0.50)=0.02 kg m⁻¹, so the tension is T=μ v²=0.02×3600=72 N.
Δ L=(TL)/(AY)=(72×0.50)/(2.0×10⁻⁶×1.2×10¹¹)=(36)/(2.4×10⁵).
Δ L=1.5×10⁻⁴ m =15×10⁻⁵ m, so x=15.
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