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Asked in JEE Main 9th Jan 1st Shift 2019 · Transverse wave on a string
The tension is M g_eff with g_eff=√g²+a², and v∝√g_eff.
(g_eff)/g=((60.5)/(60))²=1.0167, so √1+(a²)/(g²)=1.0167.
(a²)/(g²)=1.0167²-1=0.0337, giving a=0.184g≈/g5.
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