Unpolarised light is incident on the boundary between two dielectric media, whose dielectric constants are 2.8 (medium-1) and 6.8 (medium-2), respectively. To satisfy the condition, so that the reflected and refracted rays are perpendicular to each other, the angle of incidence should be tan⁻¹(1+(1…

Question

Unpolarised light is incident on the boundary between two dielectric media, whose dielectric constants are 2.8 (medium-1) and 6.8 (medium-2), respectively. To satisfy the condition, so that the reflected and refracted rays are perpendicular to each other, the angle of incidence should be tan⁻¹(1+(10)/θ)^1/2, the value of θ is . (Given for dielectric media, μᵣ=1)

Accepted Answer

7. With μᵣ=1, refractive index n=√εᵣ: n₁=√2.8, n₂=√6.8. Perpendicular reflected and refracted rays means Brewster incidence: tan i=(n₂)/(n₁)=((6.8)/(2.8))^1/2. (6.8)/(2.8)=(17)/7=1+(10)/7. So θ=7. → 7

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