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A parallel beam of monochromatic light of wavelength 600 nm passes through single slit of 0.4 mm width. Angular divergence corresponding to second order minima would be ______ ×10⁻³ rad.

Asked in JEE Main 8th April 1st Shift 2024 · Single slit diffraction

Answer: 6

Step-by-step solution

Second minimum on one side: θ₂ = (2λ)/a = (2×6×10⁻⁷)/(4×10⁻⁴) = 3×10⁻³ rad.

Angular divergence is measured between the second minima on the two sides: 2θ₂.

Divergence = 6×10⁻³ rad.

→ 6

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