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In an experiment of single slit diffraction pattern, first minimum for red light coincides with first maximum of some other wavelength. If wavelength of red light is 6600 Å, then wavelength of first maximum will be

Asked in JEE Main Online 2014 · Single slit diffraction

Answer: (2) 4400 Å

Step-by-step solution

First minimum of red: a sin θ = λ_R.

First secondary maximum of λ': a sin θ = 3/2λ'.

λ' = 2/3×6600 = 4400 Å.

Why the other options are wrong

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