In a Young's double slit experiment, the intensity at a point is (1/4)^th of the maximum intensity, the minimum distance of the point from the central maximum is ______ μm.
[Given: λ = 600 nm, d = 1.0 mm, D = 1.0 m]

Question

In a Young's double slit experiment, the intensity at a point is (1/4)^th of the maximum intensity, the minimum distance of the point from the central maximum is μm.
[Given: λ = 600 nm, d = 1.0 mm, D = 1.0 m]

Accepted Answer

200. I = Iₘₐₓ cos²φ/2 = (Iₘₐₓ)/4 ⇒ cos φ/2 = 1/2. Smallest phase: φ/2 = 60°, so φ = (2π)/3 and path difference = λ/3. (yd)/D = λ/3 ⇒ y = (λ D)/(3d) = (6×10⁻⁷×1)/(3×10⁻³) = 2×10⁻⁴ m. y = 200 μm. → 200

In a Young's double slit experiment, the intensity at a point is (1/4)^th of the maximum intensity, the minimum distance of the point from the central maximum is ______ μm.[Given: λ = 600 nm, d = 1.0 mm, D = 1.0 m]

Step-by-step solution

In a Young's double slit experiment, the intensity at a point is (1/4)^th of the maximum intensity, the minimum distance of the point from the central maximum is ______ μm.
[Given: λ = 600 nm, d = 1.0 mm, D = 1.0 m]