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In a Young's double slit experiment, the width of one of the slit is three times the other slit. The amplitude of the light coming from a slit is proportional to the slit width. Find the ratio of the maximum to the minimum intensity in the interference pattern.

Asked in JEE Main 24th Feb 1st Shift 2021 · Intensity and coherent sources

Answer: (3) 4 : 1

Step-by-step solution

Amplitudes 3 : 1

(Iₘₐₓ)/(Iₘᵢₙ) = ((3+1)/(3-1))² = 4

Why the other options are wrong

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