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In a double slit experiment with monochromatic light, fringes are obtained on a screen placed at some distance from the plane of slits. If the screen is moved by 5×10⁻² m towards the slits, the change in fringe width is 3×10⁻³ cm. If the distance between the slits is 1 mm, then the wavelength of the light will be ______ nm.

Asked in JEE Main 29th June 2nd Shift 2022 · Fringe width and fringe position

Answer: 600

Step-by-step solution

β = (λ D)/d ⇒ Δβ = (λ Δ D)/d.

λ = (d Δβ)/(Δ D) = (10⁻³×3×10⁻⁵)/(5×10⁻²) = 6×10⁻⁷ m.

λ = 600 nm.

→ 600

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