Practice portal › Wave Optics › Interference and Young's Double Slit Experiment

Two wavelengths λ₁ and λ₂ are used in Young's double slit experiment. λ₁ = 450 nm and λ₂ = 650 nm. The minimum order of fringe produced by λ₂ which overlaps with the fringe produced by λ₁ is n. The value of n is ______.

Asked in JEE Main 4th April 1st Shift 2024 · Fringe width and fringe position

Answer: 9

Step-by-step solution

Bright fringes overlap when nλ₂ = mλ₁.

650n = 450m ⇒ 13n = 9m.

Smallest integers: n = 9, m = 13.

→ 9

More Interference and Young's Double Slit Experiment questionsAll Interference and Young's Double Slit Experiment questions →

Reading this solution needs no sign-in. You only sign in to practise against the clock and keep your progress.

Practise this with a timer