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Interference fringes are observed on a screen by illuminating two thin slits 1 mm apart with a light source (λ = 632.8 nm). The distance between the screen and the slits is 100 cm. If a bright fringe is observed on a screen at a distance of 1.27 mm from the central bright fringe, then the path difference between the waves, which are reaching this point from the slits is close to

Asked in JEE Main 2nd Sept 1st Shift 2020 · Fringe width and fringe position

Answer: (1) 1.27 μm

Step-by-step solution

Δ = (yd)/D = (1.27 × 10⁻³ × 10⁻³)/1

Δ = 1.27 × 10⁻⁶ m = 1.27 μm (about 2λ, second bright fringe)

Why the other options are wrong

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