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The Young's double slit interference experiment is performed using light consisting of 480 nm and 600 nm wavelengths to form interference patterns. The least number of the bright fringes of 480 nm light that are required for the first coincidence with the bright fringes formed by 600 nm light is

Asked in JEE Main 24th Jan 1st Shift 2025 · Fringe width and fringe position

Answer: (1) 5

Step-by-step solution

Coincidence: n₁λ₁ = n₂λ₂

480 n₁ = 600 n₂ ⇒ (n₁)/(n₂) = 5/4

Least integers: n₁ = 5, n₂ = 4

Why the other options are wrong

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