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A particle of mass m with an initial velocity ûi collides perfectly elastically with a mass 3m at rest. It moves with a velocity v̂j after collision, then, v is given by

Asked in JEE Main 2nd Sept 1st Shift 2020 · Momentum components in two dimensions

Answer: (3) v=u/(√2)

Step-by-step solution

Momentum: 3m⃗V=mûi-mv̂j⇒⃗V=(ûi-v̂j)/3.

Energy: u²=v²+3((u²+v²)/9)⇒3u²=3v²+u²+v²⇒2u²=4v².

v=u/(√2).

Why the other options are wrong

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