A bag of sand of mass 9.8 kg is suspended by a rope. A bullet of 200 g travelling with speed 10 m s⁻¹ gets embedded in it, then loss of kinetic energy will be

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(2) 9.8 J. After embedding: V=(0.2×10)/(10)=0.2 m/s. Kᵢ=1/2×0.2×100=10 J; K_f=1/2×10×0.04=0.2 J. Loss =10-0.2=9.8 J.

A bag of sand of mass 9.8 kg is suspended by a rope. A bullet of 200 g travelling with speed 10 m s⁻¹ gets embedded in it, then loss of kinetic energy will be

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