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Asked in JEE Main 28th Jan 2nd Shift 2025 · Average and instantaneous power
Displacement ⃗d=(6-3)̂i+(10-4)̂j=3̂i+6̂j; work W=⃗F·⃗d=6+18=24 J.
Average power: (24)/4=6 W.
Instantaneous power at 4 s, taking the body to start from rest so ⃗v=(⃗F)/mt=(2̂i+3̂j) m/s: P=⃗F·⃗v=4+9=13 W.
Ratio 6:13. (Strictly, a start from rest would give a displacement of 4̂i+6̂j, not the stated 3̂i+6̂j; the key follows the working above.)
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