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Two solids A and B of mass 1 kg and 2 kg respectively are moving with equal linear momentum. The ratio of their kinetic energies (K.E.)_A:(K.E.)_B will be /A1, so the value of A will be ______.

Asked in JEE Main 24th Feb 2nd Shift 2021 · Relating kinetic energy to momentum

Answer: 2

Step-by-step solution

K=(p²)/(2m): (K_A)/(K_B)=(m_B)/(m_A)=2/1, so A=2.

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