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Asked in JEE Main 27th June 1st Shift 2022 · Energy in vertical circular motion
To just complete the circle on a string of length 2 m: v_b²=5gL=100⇒ v_b=10 m/s.
Momentum through the collision: 0.075v=0.075/v3+0.05×10⇒0.05v=0.5.
v=10 m s⁻¹.
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