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A particle of mass 10 g moves in a straight line with retardation 2x, where x is the displacement in SI units. Its loss of kinetic energy for above displacement is ((10)/x)⁻ⁿ J. The value of n will be ______.

Asked in JEE Main 6th April 1st Shift 2023 · Work against resistance

Answer: 2

Step-by-step solution

a=-2x⇒ v dv=-2x dx⇒1/2v²-1/2v₀²=-x².

Loss of kinetic energy: m x²=0.01x²=(x²)/(100)=((10)/x)⁻² J.

n=2.

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