Practice portal › Work, Energy and Power › Work Done by a Variable Force
Asked in JEE Main Online 2012 · Force-displacement graphs
Initial kinetic energy: 1/2×2×25=25 J.
Signed area: 0 to 2 m, triangle +1/2(2)(2)=2 J; 2 to 3 m, -1/2(1)(1)=-0.5 J; 3 to 4 m, -1 J; 4 to 5 m, -0.5 J; 5 to 8 m, +1/2(3)(3)=4.5 J.
Total work =2-0.5-1-0.5+4.5=4.5 J.
K=25+4.5=29.5 J.
Reading this solution needs no sign-in. You only sign in to practise against the clock and keep your progress.
Practise this with a timer