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A block of mass m, lying on a smooth horizontal surface, is attached to a spring (of negligible mass) of spring constant k. The other end of the spring is fixed, as shown in the figure. The block is initially at rest in its equilibrium position. If now the block is pulled with a constant force F, the maximum speed of the block is

Asked in JEE Main 9th Jan 1st Shift 2019 · Energy stored and maximum compression

Figure: Energy stored and maximum compression
Answer: (1) F/(√mk)

Step-by-step solution

Speed is maximum where the net force vanishes: kx=F⇒ x=/Fk.

Energy up to that point: 1/2mv²=Fx-1/2kx²=(F²)/k-(F²)/(2k)=(F²)/(2k).

vₘₐₓ=F/(√mk).

Why the other options are wrong

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