A particle of mass 500 gm is moving in straight line with velocity v=bx^5/2. The work done by the net force during its displacement from x=0 to x=4 m is (Take b=0.25 m^-3/2s⁻¹).

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(4) 16 J. At x=4 m: v=0.25×4^5/2=0.25×32=8 m/s; at x=0, v=0. W=Δ K=1/2×0.5×64=16 J.

A particle of mass 500 gm is moving in straight line with velocity v=bx^5/2. The work done by the net force during its displacement from x=0 to x=4 m is (Take b=0.25 m^-3/2s⁻¹).

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