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A block of mass 10 kg is moving along x-axis under the action of force F=5x N. The work done by the force in moving the block from x=2 m to 4 m will be ______ J.

Asked in JEE Main 15th April 1st Shift 2023 · Integrating a position-dependent force

Answer: 30

Step-by-step solution

W=∫₂⁴5x dx=5/2(16-4).

W=5/2×12=30 J. The mass plays no part.

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