A body of mass 0.5 kg travels on straight line path with velocity v=(3x²+4) m/s. The net work done by the force during its displacement from x=0 to x=2 m is

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(2) 60 J. Given: m=0.5 kg, v=3x²+4. v(0)=4 m/s, v(2)=3×4+4=16 m/s. Work-energy theorem: W=1/2m(v₂²-v₀²)=1/2×0.5×(256-16). W=0.25×240=60 J.

A body of mass 0.5 kg travels on straight line path with velocity v=(3x²+4) m/s. The net work done by the force during its displacement from x=0 to x=2 m is

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