Practice portal › Experimental Skills › Vernier Callipers
Asked in JEE Main 29th June 2nd Shift 2022 · Negative zero error
L.C. =0.1 mm=0.01 cm, so observed =1.70+5×0.01=1.75 cm.
Negative zero error -0.05 cm: corrected =1.75-(-0.05)=1.80 cm=180×10⁻² cm.
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