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A vernier callipers has a vernier constant of 0.1 mm and a zero error of -0.05 cm. Measuring a sphere, the main scale reads 1.7 cm and the coinciding vernier division is 5. The corrected diameter is ______ × 10⁻² cm.

Asked in JEE Main 29th June 2nd Shift 2022 · Negative zero error

Answer: 180

Step-by-step solution

L.C. =0.1 mm=0.01 cm, so observed =1.70+5×0.01=1.75 cm.

Negative zero error -0.05 cm: corrected =1.75-(-0.05)=1.80 cm=180×10⁻² cm.

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