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If n main scale divisions coincide with (n+1) vernier scale divisions and each centimetre on the main scale is divided into five equal parts, the least count of the vernier callipers will be

Asked in JEE Main 30th June 1st Shift 2022 · Least count

Answer: (1) 2/(n+1) mm

Step-by-step solution

Each cm split into 5 parts ⇒ 1 MSD =(10)/5=2 mm.

n MSD =(n+1) VSD ⇒ L.C. =1 MSD(1-n/(n+1))=2/(n+1) mm.

Why the other options are wrong

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