Practice portal › Units and Measurements › Deriving Relations by Dimensional Analysis
Asked in JEE Main Online 2015 · Deriving a relation by dimensional analysis
Given: Q/A is a power per unit area, [MT⁻³].
η=[ML⁻¹T⁻¹] and (SΔθ)/h=([L²T⁻²K⁻¹][K])/([L])=[LT⁻²].
Their product: [ML⁻¹T⁻¹][LT⁻²]=[MT⁻³].
That matches exactly, so no further factor is needed and Q/A=η(SΔθ)/h.
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