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Asked in JEE Main Online 2018 · Expressing a quantity in new base units
Given: G=[M⁻¹L³T⁻²], ℏ=[ML²T⁻¹], c=[LT⁻¹].
Gℏ=[L⁵T⁻³], the mass having cancelled.
(Gℏ)/(c³)=([L⁵T⁻³])/([L³T⁻³])=[L²].
Taking the square root gives a length, so the Planck length is ((Gℏ)/(c³))^1/2.
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