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Velocity (v) and acceleration (a) in two systems of units 1 and 2 are related as v₂=n/(m²)v₁ and a₂=(a₁)/(mn) respectively. Here m and n are constants. The relations for distance and time in two systems respectively are

Asked in JEE Main 28th June 2nd Shift 2022 · Expressing a quantity in new base units

Answer: (1) (n³)/(m³)L₁=L₂ and (n²)/mT₁=T₂

Step-by-step solution

Let x=(L₂)/(L₁) and y=(T₂)/(T₁).

Velocity: (v₂)/(v₁)=x/y=n/(m²).

Acceleration: (a₂)/(a₁)=x/(y²)=1/(mn).

Dividing the first by the second: y=n/(m²)× mn=(n²)/m.

Then x=n/(m²)×(n²)/m=(n³)/(m³).

So L₂=(n³)/(m³)L₁ and T₂=(n²)/mT₁.

Why the other options are wrong

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