Practice portal › Units and Measurements › Dimensions of Constants in Physical Relations
Asked in JEE Main 31st Jan 2nd Shift 2024 · Constants in a given relation
Idea: B-x² forces B to have the dimension of x².
B=[L²].
From E=B/(At): A=B/(Et)=([L²])/([ML²T⁻²][T])=[M⁻¹T].
AB=[M⁻¹T][L²]=[L²M⁻¹T].
Reading this solution needs no sign-in. You only sign in to practise against the clock and keep your progress.
Practise this with a timer