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Asked in JEE Main 25th July 2nd Shift 2022 · Error in a power
Idea: the heat dissipated is H=I²Rt, so the current enters squared.
(Δ H)/H=2(Δ I)/I+(Δ R)/R+(Δ t)/t
=2(2%)+1%+3%
=4%+1%+3%=8%.
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