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Asked in JEE Main 22nd Jan 2nd Shift 2025 · Percentage error in a derived quantity
Given: m=0.60±0.003 g, r=0.50±0.01 cm, l=10.00±0.05 cm.
Idea: ρ=m/(π r²l), so the radius enters squared.
(Δρ)/ρ=(Δ m)/m+2(Δ r)/r+(Δ l)/l
=(0.003)/(0.60)+2×(0.01)/(0.50)+(0.05)/(10.00)
=0.005+0.040+0.005=0.05, that is 5%.
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