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Asked in JEE Main Online 2012 · Junction temperature
Given: equal lengths L/2 and equal areas, with K_Cu=9Kₛ.
Idea: in the steady state the heat currents through the two halves are equal, so set them equal rather than averaging the end temperatures.
(9KₛA(100-T))/(L/2)=(KₛA(T-0))/(L/2), and everything common cancels.
9(100-T)=T, so 900=10T.
T=90 °C; the junction sits close to the hot end because the copper offers almost no resistance.
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