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Asked in JEE Main 4th April 1st Shift 2024 · Temperature scales
Given: a temperature difference, not a temperature reading.
Between the ice and steam points there are 100 Celsius divisions and 212-32=180 Fahrenheit divisions, so Δ F=(180)/(100)Δ C=9/5Δ C.
The 32 in F=9/5C+32 is an offset of the zero, and it cancels in any difference.
Δ F=9/5×40=72 °F.
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