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Asked in JEE Main 2nd April 2nd Shift 2025 · Molar Specific Heats and Degrees of Freedom
Air is diatomic, so U=nC_VT=5/2nRT=5/2PV.
V=4×4×3=48 m³ and P=1.013×10⁵ Pa.
U=2.5×1.013×10⁵×48=1.216×10⁷ J =12.2×10⁶ J.
To the nearest integer, 12.
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