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Asked in JEE Main 24th Feb 2nd Shift 2021 · Cycles with an Adiabatic Leg
A to B, isothermal, pressure halved so volume doubles: W_AB=RT ln 2.
B to C, constant volume: W_BC=0, and the pressure falls to (P₁)/4.
C to A, adiabatic compression from ((P₁)/4,2V₁) back to (P₁,V₁):
W_CA=(P_CV_C-P_AV_A)/(γ-1)=((P₁V₁)/2-P₁V₁)/(γ-1)=-(RT)/(2(γ-1)).
W=RT ln 2-(RT)/(2(γ-1)).
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