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n moles of a perfect gas undergo a cyclic process ABCA, shown in the figure, consisting of the following processes. A→ B: isothermal expansion at temperature T so that the volume is doubled from V₁ to V₂=2V₁ and the pressure changes from P₁ to P₂. B→ C: isobaric compression at pressure P₂ back to the initial volume V₁. C→ A: isochoric change leading to a change of pressure from P₂ to P₁. The total work done in the complete cycle ABCA is

Asked in JEE Main 24th Feb 1st Shift 2021 · Sequential Processes

Figure: Sequential Processes
Answer: (1) nRT(ln 2-1/2)

Step-by-step solution

A to B, isothermal doubling: W_AB=nRT ln 2.

B to C, isobaric compression at P₂ from 2V₁ to V₁:

W_BC=P₂(V₁-2V₁)=-P₂V₁, and P₂=(nRT)/(2V₁), so W_BC=-(nRT)/2.

C to A, isochoric: W_CA=0.

W=nRT(ln 2-1/2).

Why the other options are wrong

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