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A small square loop of wire of side l is placed inside a large square loop of wire of side L (L = l²). The loops are coplanar and their centres coincide. The value of the mutual inductance of the system is × 10⁻⁷ H, where x = _____.

Asked in JEE Main 31st Jan 1st Shift 2024 · Standard coil geometries

Answer: 128

Step-by-step solution

M=(2√2μ₀l²)/(π L), and with L=l² this reduces to M=(2√2μ₀)/π.

Putting μ₀=4π×10⁻⁷ gives M=8√2×10⁻⁷ H, so x=8√2≈11.3; the printed value 128 corresponds to x², so check this one against the key before use.

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