A metal conductor of length 1 m rotates vertically about one of its ends at angular velocity 5 radian per second. If the horizontal component of earth's magnetic field is 0.2 × 10⁻⁴ T, then the e.m.f. developed between the two ends of the conductor is

Question

Accepted Answer

(2) 50 μV. ε=1/2B_Hω L²=1/2×0.2×10⁻⁴×5×1=50 .

A metal conductor of length 1 m rotates vertically about one of its ends at angular velocity 5 radian per second. If the horizontal component of earth's magnetic field is 0.2 × 10⁻⁴ T, then the e.m.f. developed between the two ends of the conductor is

Step-by-step solution