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An aeroplane with its wings spread 10 m is flying at a speed of 180 km/h in a horizontal direction. The total intensity of earth's field at that part is 2.5 × 10⁻⁴ Wb/m² and the angle of dip is 60°. The emf induced between the tips of the plane wings will be _____.

Asked in JEE Main 26th Feb 2nd Shift 2021 · Free conductor moving in a field

Answer: (3) 108.25 mV

Step-by-step solution

Only the vertical component threads the horizontal wings: B_V=B sin δ=2.5×10⁻⁴ sin 60°=2.165×10⁻⁴ T.

v=180 km h⁻¹=50 m s⁻¹.

ε=B_Vℓ v=2.165×10⁻⁴×10×50=108.25 mV.

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