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Asked in JEE Main 2nd April 2nd Shift 2026 · Positive zero error
L.C. =(0.1)/(100)=0.001 mm.
Positive zero error =5×0.001=0.005 mm (reference at the 5th division when closed).
Observed =5+50×0.001=5.05 mm.
Corrected =5.05-0.005=5.045 mm.
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