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Using a screw gauge of pitch 0.1 cm and 50 divisions on its circular scale, the thickness of an object is measured. It should correctly be recorded as

Asked in JEE Main 3rd Sept 1st Shift 2020 · Pitch and least count

Answer: (2) 2.124 cm

Step-by-step solution

L.C. =(0.1 cm)/(50)=0.002 cm.

A recorded reading must be a whole number of least counts.

Only 2.124=1062×0.002 qualifies; 2.121, 2.123, 2.125 are not multiples of 0.002.

Why the other options are wrong

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