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The correct truth table for the following logic circuit is [Figure: A passes through a NOT gate into an OR gate; A and B also feed an AND gate whose output is the other OR input; the OR output is Y. Options list Y for AB=00,01,10,11: (a) 1,1,0,0; (b) 0,0,0,1; (c) 1,1,0,1; (d) 0,1,0,1.]
Asked in JEE Main 6th April 1st Shift 2024 · Gate combinations and truth tables
- (1) 1,1,0,0
- (2) 0,0,0,1
- (3) 1,1,0,1
- (4) 0,1,0,1
Answer: (3) 1,1,0,1
Step-by-step solution
Y=A+AB=A+B
00→1, 01→1, 10→0, 11→1.
Why the other options are wrong
- (1) Misses the AB term, which gives 1 for A=B=1.
- (2) Keeps only the AB term.
- (4) Misses the A term, which gives 1 for A=B=0.
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