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Consider the following logic circuit. The output is Y=0 when [Figure: A and B feed an AND gate. B and A (from A through a NOT gate) feed an OR gate. The AND and OR outputs feed a NAND gate whose output is Y.]

Asked in JEE Main 7th April 2nd Shift 2025 · Gate combinations and truth tables

Figure: Gate combinations and truth tables
Answer: (2) A=1 and B=1

Step-by-step solution

Y=AB·(A+B)

AB(A+B)=ABA+AB=AB

Y=AB, which is 0 only for A=1,B=1.

Why the other options are wrong

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