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A Zener diode is connected to a battery and a load as shown below. The currents I, I_Z and I_L are respectively [Figure: a 60 V battery, 4 kΩ in series to node A, a Zener (V_Z=10 V) from A to B, and R_L=2 kΩ in parallel with it.]

Asked in JEE Main Online 2014 · Zener current and series resistance

Figure: Zener current and series resistance
Answer: (4) 12.5 mA, 7.5 mA, 5 mA

Step-by-step solution

I=(60-10)/(4 kΩ)=12.5 mA

I_L=(10)/(2 kΩ)=5 mA

I_Z=12.5-5=7.5 mA

Why the other options are wrong

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