The current voltage relation of diode is given by I=(e^1000V/T-1) mA, where the applied voltage V is in volts and the temperature T is in degree Kelvin. If a student makes an error measuring ±0.01 V while measuring the current of 5 mA at 300 K, what will be the error in the value of current in mA?

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(2) 0.2 mA. (dI)/(dV)=(1000)/Te^1000V/T mA per volt. At I=5 mA: e^1000V/T=I+1=6. Δ I=(1000)/(300)×6×0.01 Δ I=0.2 mA

The current voltage relation of diode is given by I=(e^1000V/T-1) mA, where the applied voltage V is in volts and the temperature T is in degree Kelvin. If a student makes an error measuring ±0.01 V while measuring the current of 5 mA at 300 K, what will be the error in the value of current in mA?

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