In a microscope the objective is having focal length f₀ = 2 cm and eye-piece is having focal length fₑ = 4 cm. The tube length is 32 cm. The magnification produced by this microscope for normal adjustment is .

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100. Normal adjustment: m = L/(f₀)·D/(fₑ) m = (32)/2×(25)/4 = 16×6.25 m = 100 → 100

In a microscope the objective is having focal length f₀ = 2 cm and eye-piece is having focal length fₑ = 4 cm. The tube length is 32 cm. The magnification produced by this microscope for normal adjustment is ______.

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