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A diverging lens with magnitude of focal length 25 cm is placed at a distance of 15 cm from a converging lens of magnitude of focal length 20 cm. A beam of parallel light falls on the diverging lens. The final image formed is

Asked in JEE Main 2017 · Combinations and silvered lenses

Answer: (1) real and at a distance of 40 cm from convergent lens.

Step-by-step solution

Diverging lens: parallel light gives a virtual image at its focus, 25 cm in front of it.

This point is 25 + 15 = 40 cm from the converging lens: u = -40 cm.

1/v = 1/(20) - 1/(40) = 1/(40)

v = +40 cm: real image 40 cm beyond the converging lens.

Why the other options are wrong

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