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Let the refractive index of a denser medium with respect to a rarer medium be n₁₂ and its critical angle θ_C. At an angle of incidence A when light is travelling from denser medium to rarer medium, a part of the light is reflected and the rest is refracted and the angle between reflected and refracted rays is 90°. Angle A is given by

Asked in JEE Main Online 2017 · Total internal reflection and optical fibres

Answer: (3) tan⁻¹(sin θ_C)

Step-by-step solution

Reflected and refracted rays perpendicular: A+r=90°.

n₁₂ sin A=sin r=cos A⇒tan A=1/(n₁₂).

sin θ_C=1/(n₁₂)⇒ A=tan⁻¹(sin θ_C).

Why the other options are wrong

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