Practice portal › Ray Optics and Optical Instruments › Reflection by Plane and Spherical Mirrors
Asked in JEE Main 4th April 1st Shift 2026 · Mirror formula and magnification
Given: f=-10 cm, near end of rod at u₁=-20 cm, far end at u₂=-30 cm.
Near end is at C (R=20 cm), so its image is at v₁=-20 cm.
Far end: 1/(v₂)=1/f-1/(u₂)=-1/(10)+1/(30)=-1/(15), so v₂=-15 cm.
Image length =|v₁-v₂|=20-15=5 cm.
Reading this solution needs no sign-in. You only sign in to practise against the clock and keep your progress.
Practise this with a timer